Possibility of example SQL script for CB Query

Paladin Brewer
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8 years 9 months ago #287760 by Paladin Brewer

Possibility of example SQL script for CB Query was created by Paladin Brewer

Hi guys,

So I don't know if this is asking too much, but I want to do an SQL query with my photo gallery (I use Simgallery) so the Profiles can show users albums, pictures, and videos.

The actual number is not in the database, I need a counter. The tables look like this:

Code:

<table name="upa1d_simgallery_media">
<column name="mid">2</column>
<column name="owner">993</column>
<column name="type">photo</column>
<column name="typeid">1</column>
</table>
<table name="upa1d_simgallery_media">
<column name="mid">3</column>
<column name="owner">993</column>
<column name="type">photo</column>
<column name="typeid">2</column>
</table>
<table name="upa1d_simgallery_media">
<column name="mid">4</column>
<column name="owner">993</column>
<column name="type">photo</column>
<column name="typeid">3</column>
</table>
<table name="upa1d_simgallery_media">
<column name="mid">5</column>
<column name="owner">993</column>
<column name="type">photo</column>
<column name="typeid">4</column>
</table>
<table name="upa1d_simgallery_media">
<column name="mid">6</column>
<column name="owner">993</column>
<column name="type">photo</column>
<column name="typeid">5</column>
</table>

So basically I need some sort of SQL query that:
1. Accesses the database
2. Looks only for the info of whoever's profile we're on
3. Searches that specific "owner" for the type=photo
4. Counts them, and displays that number.

That make sense? My SQL is horrible so, any possible help here would be super appreciated.

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krileon
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8 years 9 months ago #287772 by krileon

Replied by krileon on topic Possibility of example SQL script for CB Query

That's a simple count select query. Example as follows based of your criteria.

Code:

SELECT COUNT(*) FROM `#__simgallery_media` WHERE `owner` = '[user_id]' AND `type` = 'photo'

See the below for some SQL learning resources.

www.w3schools.com/sql/default.asp
dev.mysql.com/doc/refman/5.6/en/entering-queries.html

Kyle (Krileon)
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Paladin Brewer
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8 years 9 months ago - 8 years 9 months ago #287774 by Paladin Brewer

Replied by Paladin Brewer on topic Possibility of example SQL script for CB Query

Thanks...so I copied/pasted that as a query. The field is published and it is Internal DB, etc, everything else is default...but the field doesn't even show up? Is there something else I need to do for query fields?

EDIT: I also tried adding a semicolon to the end to see if that was the problem but still no field is showing up.

Last edit: 8 years 9 months ago by Paladin Brewer.

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krileon
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8 years 9 months ago - 8 years 9 months ago #287778 by krileon

Replied by krileon on topic Possibility of example SQL script for CB Query

What fieldtype are you using exactly? It should strictly be Query and not a Query Select nor should you be using the Query Validation parameters on a text field for example. See the below videos on how to use CB Query Field.

www.youtube.com/playlist?list=PLp0puRITgC7MM9iP9FooKB1qk8f5MLWVp

Also ensure CB Query Field plugin is published within CB > Plugin Management.

Last edit: 8 years 9 months ago by krileon.

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Paladin Brewer
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8 years 9 months ago #287779 by Paladin Brewer

Replied by Paladin Brewer on topic Possibility of example SQL script for CB Query

Oops, I didn't have the plugin published, embarrassing. Working now, much thanks!

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Paladin Brewer
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8 years 9 months ago #287800 by Paladin Brewer

Replied by Paladin Brewer on topic Possibility of example SQL script for CB Query

If you can help me with 1 more query, I'd appreciate it. I want to do another query to show what usergroup someone is in. The problem is it doesn't directly show the person's usergroup, I have to refer to a few tables:

Code:

<table name="upa1d_user_usergroup_map">
<column name="user_id">993</column>
<column name="group_id">8</column>
</table>

Code:

<table name="upa1d_usergroups">
<column name="id">8</column>
<column name="parent_id">1</column>
<column name="lft">20</column>
<column name="rgt">21</column>
<column name="title">Super Users</column>
</table>

So user 993 (that's me) is in group_id 8, and group id 8's title is "Super Users" which is what I want to display. I've tried it, but I break it everytime

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